LeetCode July - Day 14

Problem Statement

Given two numbers, hour and minutes. Return the smaller angle (in degrees) formed between the hour and the minute hand.

Constraints:
1 <= hour <= 12
0 <= minutes <= 59

Answers within 10^-5 of the actual value will be accepted as correct.

Input: hour = 12, minutes = 30
Output: 165

Input: hour = 3, minutes = 15
Output: 7.5

Input: hour = 4, minutes = 50
Output: 155

Inputs, Outputs, Constraints & Exceptions

• I: number {h}, number {n}
• O: number {angle}
• C: optimise
• E: hour = 12, minutes = 0

hourAngle = 30 * h + m/60 minAngle = 6 * m

Code

function angleClock(hours, minutes){
  let hourAngle = 30 * (hours + minutes / 60);
  let minAngle = 6 * minutes;
  let angle = Math.abs(hourAngle - minAngle);
  if(angle > 180) angle = 360 - angle;
  return angle;
}

Time complexity: O(1)
Space complexity: O(1)